Acid dissociation constant
Expression for Ka of a weak acid.
This public page keeps the free explanation visible and leaves premium worked solving, advanced walkthroughs, and saved study tools inside the app.
Core idea
Overview
The acid dissociation constant, Ka, is an equilibrium constant that measures the quantitative strength of an acid in an aqueous solution. It describes the ratio of the concentrations of the dissociated ions to the undissociated acid molecules at equilibrium.
When to use: This equation is used when calculating the extent of ionization for weak acids in water, as strong acids are assumed to dissociate completely. It is applicable in scenarios involving pH determination, buffer capacity calculations, and titration analysis in dilute solutions.
Why it matters: Ka values allow chemists to predict the acidity of a solution and the protonation state of molecules, which is vital in drug design and biochemistry. Understanding these constants is essential for controlling chemical reactions in industrial processes where pH must remain within a specific range.
Symbols
Variables
[H^+] = Hydrogen Ion, [A^-] = Conjugate Base, acid = Acid, K_a = Acid Dissociation Constant
Walkthrough
Derivation
Understanding Acid Dissociation Constant (Ka)
Quantifies the extent to which a weak acid dissociates in water; larger Ka means a stronger acid.
- Acid is weak (partial dissociation).
State the Expression:
For HA \rightleftharpoons H^+ + A^-.
Common Weak-Acid Approximation:
If dissociation is small, $[HA]_{eq} \approx [HA]_{initial}$ and $[H^+]\approx[A^-]$.
Result
Source: Edexcel A-Level Chemistry — Acid-Base Equilibria
Free formulas
Rearrangements
Solve for
Make Ka the subject
Ka is already the subject of the formula.
Difficulty: 1/5
Solve for
Make [HA] the subject
Start with the acid dissociation constant formula. To make [HA] the subject, first multiply both sides by [HA] to clear the denominator, then divide both sides by K_a.
Difficulty: 2/5
Solve for
Make [H^+] the subject
Start from the acid dissociation constant. Multiply both sides by [HA] and then divide by [A^-] to isolate [H^+].
Difficulty: 2/5
Solve for
Make [A^-] the subject
Start from the acid dissociation constant formula. To make [A^-] the subject, first multiply by [HA], then divide by [H^+].
Difficulty: 2/5
The static page shows the finished rearrangements. The app keeps the full worked algebra walkthrough.
Visual intuition
Graph
The graph is a straight line passing through the origin with a slope determined by the product of hydrogen and conjugate base concentrations. This linear relationship means that doubling the concentration of the acid directly doubles the product of the dissociated ions. For a chemistry student, this shows that as the acid concentration increases, the product of the ion concentrations must also increase proportionally to maintain a constant Ka. The most important feature is that the line passes through the origin, m
Graph type: linear
Why it behaves this way
Intuition
Imagine a dynamic balance where acid molecules are constantly breaking apart into ions and reforming, with K_a quantifying the preference for ions over intact molecules at equilibrium.
Signs and relationships
- Denominator [HA]: The concentration of the undissociated acid is in the denominator because it represents the reactant in the dissociation equilibrium.
- Numerator [H^+][A^-]: The product of the concentrations of the dissociated ions is in the numerator because they represent the products of the dissociation reaction.
Free study cues
Insight
Canonical usage
In introductory chemistry, K_a is typically treated as having units of concentration (e.g., mol/L or M) when molar concentrations are used in its calculation.
Common confusion
The primary confusion arises from whether K_a should have units or be dimensionless. This depends on whether concentrations are treated as activities (dimensionless) or molarities (with units of mol/L).
Dimension note
Although the acid dissociation constant K_a is strictly dimensionless when defined using activities, it is frequently treated as having units of concentration (e.g., mol/L or M)
Unit systems
Ballpark figures
- Quantity:
One free problem
Practice Problem
A 0.10 M solution of a generic weak acid HA reaches equilibrium. The concentration of both H⁺ and A⁻ ions is measured to be 0.00134 M, and the remaining undissociated HA is 0.09866 M. Calculate the acid dissociation constant Ka.
Solve for: Ka
Hint: Square the ion concentration and divide by the concentration of the neutral acid.
The full worked solution stays in the interactive walkthrough.
Where it shows up
Real-World Context
Finding Ka of ethanoic acid from equilibrium data.
Study smarter
Tips
- Larger Ka values correspond to stronger acids with higher degrees of ionization.
- The concentration of liquid water is constant and therefore omitted from the expression.
- At 25°C, pKa is calculated as the negative base-10 logarithm of Ka.
Avoid these traps
Common Mistakes
- Using initial instead of equilibrium concentrations.
- Forgetting the denominator.
Common questions
Frequently Asked Questions
Quantifies the extent to which a weak acid dissociates in water; larger Ka means a stronger acid.
This equation is used when calculating the extent of ionization for weak acids in water, as strong acids are assumed to dissociate completely. It is applicable in scenarios involving pH determination, buffer capacity calculations, and titration analysis in dilute solutions.
Ka values allow chemists to predict the acidity of a solution and the protonation state of molecules, which is vital in drug design and biochemistry. Understanding these constants is essential for controlling chemical reactions in industrial processes where pH must remain within a specific range.
Using initial instead of equilibrium concentrations. Forgetting the denominator.
Finding Ka of ethanoic acid from equilibrium data.
Larger Ka values correspond to stronger acids with higher degrees of ionization. The concentration of liquid water is constant and therefore omitted from the expression. At 25°C, pKa is calculated as the negative base-10 logarithm of Ka.
References
Sources
- IUPAC Gold Book: Acid dissociation constant
- Atkins' Physical Chemistry
- Wikipedia: Acid dissociation constant
- IUPAC Gold Book: 'acid dissociation constant'
- General Chemistry: Principles and Modern Applications by Petrucci, Herring, Madura, Bissonnette
- Atkins' Physical Chemistry, 11th Edition
- Edexcel A-Level Chemistry — Acid-Base Equilibria