Van't Hoff Equation (Equilibrium Constant vs. Temperature)
Relates the equilibrium constant of a reaction to temperature, standard enthalpy change, and standard entropy change.
This public page keeps the free explanation visible and leaves premium worked solving, advanced walkthroughs, and saved study tools inside the app.
Core idea
Overview
The Van't Hoff equation is a fundamental thermodynamic relationship that describes how the equilibrium constant (K) of a chemical reaction changes with temperature (T). It connects the macroscopic observable K with the microscopic thermodynamic properties of the reaction: the standard enthalpy change (ΔH°) and standard entropy change (ΔS°). This equation is crucial for predicting the shift in equilibrium position under varying thermal conditions and for determining thermodynamic parameters from experimental equilibrium data.
When to use: Apply this equation when you need to predict the equilibrium constant at a different temperature, or when you want to determine the standard enthalpy or entropy change of a reaction from experimental equilibrium constant data at various temperatures. It's particularly useful for understanding the temperature dependence of industrial processes and biological systems.
Why it matters: The Van't Hoff equation is vital for optimizing chemical processes, designing catalysts, and understanding natural phenomena. It allows chemists to predict how changes in temperature will affect product yield, which is critical in industrial synthesis. In biochemistry, it helps explain how temperature influences enzyme activity and biological equilibria.
Symbols
Variables
K = Equilibrium Constant, K = Natural Log of Equilibrium Constant, H^ = Standard Enthalpy Change, R = Gas Constant, T = Temperature
Walkthrough
Derivation
Formula: Van't Hoff Equation
The Van't Hoff equation describes the temperature dependence of the equilibrium constant for a chemical reaction.
- ΔH° and ΔS° are constant over the temperature range considered.
- The reaction is at equilibrium.
- Ideal gas behavior for gaseous components or ideal solution behavior for dissolved components.
Relate Gibbs Free Energy to Equilibrium Constant:
The standard Gibbs free energy change (ΔG°) is related to the equilibrium constant (K) at a given temperature (T) by this fundamental thermodynamic equation, where R is the gas constant.
Relate Gibbs Free Energy to Enthalpy and Entropy:
The standard Gibbs free energy change is also defined in terms of the standard enthalpy change (ΔH°) and standard entropy change (ΔS°) of the reaction.
Equate the Expressions for ΔG°:
By equating the two expressions for ΔG°, we link the equilibrium constant to the enthalpy and entropy changes.
Rearrange to Isolate ln K:
Divide the entire equation by -RT to make ln K the subject.
Simplify the Expression:
Simplify the second term by canceling T from the numerator and denominator, yielding the Van't Hoff equation.
Result
Source: Physical Chemistry by P.W. Atkins and J. de Paula, 11th Edition — Chapter 6: Chemical Equilibrium
Free formulas
Rearrangements
Solve for
Make K the subject
Exact symbolic rearrangement generated deterministically for K.
Difficulty: 3/5
Solve for
Make deltaH the subject
Exact symbolic rearrangement generated deterministically for deltaH.
Difficulty: 3/5
Solve for
Make R the subject
R = \frac{- \Delta H^\circ + T \Delta S^\circ}{T \ln\left(K \right)}}Exact symbolic rearrangement generated deterministically for R.
Difficulty: 3/5
Solve for
Make T the subject
T = - \frac{\Delta H^\circ}{R \ln\left(K \right)} - \Delta S^\circ}Exact symbolic rearrangement generated deterministically for T.
Difficulty: 3/5
Solve for
Make deltaS the subject
\Delta S^\circ = \frac{\Delta H^\circ}{T} + R \ln\left(K \right)}Exact symbolic rearrangement generated deterministically for deltaS.
Difficulty: 3/5
The static page shows the finished rearrangements. The app keeps the full worked algebra walkthrough.
Visual intuition
Graph
The graph follows a hyperbolic curve because the temperature variable is located in the denominator, resulting in a horizontal asymptote at the value of the standard entropy change divided by the gas constant. For a chemistry student, this shape illustrates that as temperature increases toward large values, the natural log of the equilibrium constant approaches a fixed limit determined by entropy, whereas at low temperatures, the enthalpy term exerts a much more dominant influence on the equilibrium. The most important feature of this curve is that it is restricted to positive temperature values and never crosses its horizontal asymptote, meaning the ratio of entropy to the gas constant represents a theoretical ceiling or floor for the reaction's equilibrium state.
Graph type: hyperbolic
Why it behaves this way
Intuition
Plotting the natural logarithm of the equilibrium constant (ln K) against the reciprocal of the absolute temperature (1/T) yields a straight line, where the slope is -ΔH°/R and the y-intercept is ΔS°/R.
Signs and relationships
- -\frac{Δ H^°}{RT}: The negative sign in front of the enthalpy term indicates an inverse relationship between temperature and the equilibrium constant for exothermic reactions (ΔH° < 0), and a direct relationship for endothermic reactions
Free study cues
Insight
Canonical usage
This equation requires consistent SI units for thermodynamic quantities (J for energy, K for temperature, mol for amount) to ensure the terms on the right-hand side are dimensionless, matching the dimensionless nature of
Common confusion
A common mistake is using temperature in Celsius instead of Kelvin, or using inconsistent energy units for ΔH° (e.g., kJ mol^-1) and R (J mol^-1 K^-1) without proper conversion.
Unit systems
One free problem
Practice Problem
For a reaction, the standard enthalpy change (ΔH°) is -50,000 J/mol and the standard entropy change (ΔS°) is -100 J/mol K. Calculate the natural logarithm of the equilibrium constant (ln K) at 298 K. Use R = 8.314 J/mol K.
Solve for: lnK
Hint: Ensure all units are consistent (Joules for energy terms).
The full worked solution stays in the interactive walkthrough.
Where it shows up
Real-World Context
Predicting the optimal temperature for ammonia synthesis in the Haber-Bosch process to maximize yield.
Study smarter
Tips
- Ensure temperature 'T' is always in Kelvin (K).
- The gas constant 'R' must be chosen with units consistent with ΔH° and ΔS° (e.g., 8.314 J mol⁻¹ K⁻¹).
- ΔH° and ΔS° should be in consistent units (e.g., J mol⁻¹ and J mol⁻¹ K⁻¹).
- A plot of ln K vs. 1/T yields a straight line with a slope of -ΔH°/R and a y-intercept of ΔS°/R.
Avoid these traps
Common Mistakes
- Using Celsius instead of Kelvin for temperature.
- Inconsistent units for R, ΔH°, and ΔS° (e.g., kJ for ΔH° and J for R/ΔS°).
- Confusing the Van't Hoff equation with the Arrhenius equation (which relates rate constant to temperature).
Common questions
Frequently Asked Questions
The Van't Hoff equation describes the temperature dependence of the equilibrium constant for a chemical reaction.
Apply this equation when you need to predict the equilibrium constant at a different temperature, or when you want to determine the standard enthalpy or entropy change of a reaction from experimental equilibrium constant data at various temperatures. It's particularly useful for understanding the temperature dependence of industrial processes and biological systems.
The Van't Hoff equation is vital for optimizing chemical processes, designing catalysts, and understanding natural phenomena. It allows chemists to predict how changes in temperature will affect product yield, which is critical in industrial synthesis. In biochemistry, it helps explain how temperature influences enzyme activity and biological equilibria.
Using Celsius instead of Kelvin for temperature. Inconsistent units for R, ΔH°, and ΔS° (e.g., kJ for ΔH° and J for R/ΔS°). Confusing the Van't Hoff equation with the Arrhenius equation (which relates rate constant to temperature).
Predicting the optimal temperature for ammonia synthesis in the Haber-Bosch process to maximize yield.
Ensure temperature 'T' is always in Kelvin (K). The gas constant 'R' must be chosen with units consistent with ΔH° and ΔS° (e.g., 8.314 J mol⁻¹ K⁻¹). ΔH° and ΔS° should be in consistent units (e.g., J mol⁻¹ and J mol⁻¹ K⁻¹). A plot of ln K vs. 1/T yields a straight line with a slope of -ΔH°/R and a y-intercept of ΔS°/R.
References
Sources
- Atkins' Physical Chemistry
- Wikipedia: Van 't Hoff equation
- Callen, Herbert B. Thermodynamics and an Introduction to Thermostatistics
- NIST CODATA
- IUPAC Gold Book: 'equilibrium constant'
- IUPAC Gold Book: 'standard enthalpy of reaction'
- IUPAC Gold Book: 'standard entropy of reaction'
- Atkins' Physical Chemistry, 11th ed.