Generating Functions (Coefficient)
Coefficient of x^n in (1−x)^{−k}.
This public page keeps the free explanation visible and leaves premium worked solving, advanced walkthroughs, and saved study tools inside the app.
Core idea
Overview
This formula identifies the coefficient of xⁿ in the power series expansion of (1-x)⁻ᵏ, representing the fundamental tool for counting combinations with repetition. In combinatorics, it provides the closed-form solution for distributing n identical items into k distinct categories, often referred to as the stars and bars method.
When to use: Apply this equation when you need to find the number of ways to select n items from k types with replacement allowed. It is also the standard method for finding specific terms in the expansion of rational generating functions where the denominator is a power of a linear binomial.
Why it matters: It bridges algebra and discrete mathematics, allowing complex counting problems to be solved via polynomial manipulation. This is essential in probability theory for negative binomial distributions and in computer science for analyzing the complexity of nested loops.
Symbols
Variables
a_n = Coefficient, n = Power n, k = Parameter k
Walkthrough
Derivation
Coefficient Identity for (1−x)^{−k}
The coefficient of in (1−x)^{−k} is C(n+k−1,k−1).
- n is an integer ≥ 0.
- k is an integer ≥ 1.
State the standard series expansion:
This is a classical generating function identity used in stars-and-bars counting.
Read off the coefficient of x^n:
The coefficient is the binomial coefficient shown.
Result
Free formulas
Rearrangements
Solve for
Make the subject
This identity directly defines the coefficient of in the power series expansion of (1-x)^{-k} as a binomial coefficient. The goal is to state this known combinatorial form.
Difficulty: 2/5
The static page shows the finished rearrangements. The app keeps the full worked algebra walkthrough.
Visual intuition
Graph
Graph unavailable for this formula.
The graph displays a power-law curve where the coefficient increases as the independent variable n grows. Because the formula is equivalent to a polynomial in n of degree k-1, the shape transitions from constant to linear or higher-order polynomial growth depending on the fixed value of k.
Graph type: power_law
Why it behaves this way
Intuition
Visualize 'n' identical items (stars) arranged in a row, with 'k-1' identical dividers (bars) placed among them to partition the items into 'k' distinct groups, where the total number of arrangements of these stars and
Signs and relationships
- -k: The negative exponent arises from the algebraic manipulation of the geometric series 1/(1-x). When raised to a negative power 'k', it corresponds to multiplying 'k' such series, which is the algebraic representation of
- k-1: This term represents the number of 'bars' needed to divide 'n' identical items ('stars') into 'k' distinct bins. For 'k' bins, 'k-1' dividers are required, which is a core component of the 'stars and bars' combinatorial
- n+k-1: This represents the total number of 'positions' available when arranging 'n' identical items (stars) and 'k-1' identical dividers (bars).
Free study cues
Insight
Canonical usage
This equation is used in combinatorics to count the number of combinations with repetition, and all quantities involved are dimensionless counts or formal mathematical variables.
Common confusion
A common mistake is to attempt to assign physical units to the formal variable 'x' or to the counts 'n' and 'k', when in this context, they are inherently dimensionless mathematical constructs.
Dimension note
All variables (n, k) and the result (the binomial coefficient) represent counts or formal variables, making the entire equation fundamentally dimensionless.
Unit systems
One free problem
Practice Problem
Find the coefficient of in (1−x)^{−3}.
Solve for:
Hint: Coefficient is C(n+k−1,k−1)=C(6,2).
The full worked solution stays in the interactive walkthrough.
Where it shows up
Real-World Context
Counting solutions to x1+x2+...+xk=n with xi≥0.
Study smarter
Tips
- The value of [xⁿ](1-x)⁻ᵏ is equivalent to (n+k-1) choose n.
- Always ensure the inner term is in the form (1-x); if it is (1-ax), the result must be multiplied by aⁿ.
- If you have lower bounds on variables (e.g., at least one item per bin), subtract those constants from n first.
Avoid these traps
Common Mistakes
- Using C(n,k) instead of C(n+k−1,k−1).
- Forgetting k must be at least 1.
Common questions
Frequently Asked Questions
The coefficient of x^n in (1−x)^{−k} is C(n+k−1,k−1).
Apply this equation when you need to find the number of ways to select n items from k types with replacement allowed. It is also the standard method for finding specific terms in the expansion of rational generating functions where the denominator is a power of a linear binomial.
It bridges algebra and discrete mathematics, allowing complex counting problems to be solved via polynomial manipulation. This is essential in probability theory for negative binomial distributions and in computer science for analyzing the complexity of nested loops.
Using C(n,k) instead of C(n+k−1,k−1). Forgetting k must be at least 1.
Counting solutions to x1+x2+...+xk=n with xi≥0.
The value of [xⁿ](1-x)⁻ᵏ is equivalent to (n+k-1) choose n. Always ensure the inner term is in the form (1-x); if it is (1-ax), the result must be multiplied by aⁿ. If you have lower bounds on variables (e.g., at least one item per bin), subtract those constants from n first.
References
Sources
- Concrete Mathematics: A Foundation for Computer Science by Ronald L. Graham, Donald E. Knuth, Oren Patashnik, Chapter 7
- A First Course in Probability by Sheldon Ross, Chapter 2
- Wikipedia: Generating function
- Wikipedia: Stars and bars (combinatorics)
- Concrete Mathematics: A Foundation for Computer Science by Ronald L. Graham, Donald E. Knuth, Oren Patashnik
- Discrete Mathematics and Its Applications by Kenneth H. Rosen
- Generating function (Wikipedia article)
- Richard P. Stanley, Enumerative Combinatorics Volume 1