Fick's Law of Diffusion
Fick's Law states that the rate of diffusion is directly proportional to the surface area and the concentration gradient, and inversely proportional to the diffusion distance.
This public page keeps the free explanation visible and leaves premium worked solving, advanced walkthroughs, and saved study tools inside the app.
Core idea
Overview
This relationship explains the physiological adaptations of gas exchange surfaces, such as alveoli in lungs or villi in the small intestine. By maximizing surface area and maintaining a steep concentration gradient while minimizing membrane thickness, organisms ensure efficient exchange of gases and nutrients. It is the fundamental physical principle governing cellular respiration and homeostatic exchange.
When to use: Apply this when calculating factors affecting the efficiency of gas exchange surfaces or cellular diffusion rates.
Why it matters: It explains why respiratory surfaces (like gills or lungs) are highly branched or folded and why capillary walls are only one cell thick.
Symbols
Variables
k = Diffusion Constant, A = Surface Area, C = Concentration Gradient, d = Diffusion Distance, rate = Rate of Diffusion
Walkthrough
Derivation
Derivation of Fick's Law of Diffusion
Fick's Law relates the rate of molecular diffusion to the physical properties of a membrane and the chemical gradient across it. It is derived from the observation of mass flux in a steady-state system.
- The membrane is a thin, flat barrier separating two regions.
- Diffusion occurs in a steady state where the concentration gradient remains constant over time.
- The particles behave as an ideal gas or solute in a solvent.
Defining Net Flux
Starting with Fick's First Law for 1D diffusion, where J is the molar flux (amount per unit area per unit time), D is the diffusion coefficient, and dC/dx is the concentration gradient.
Note: The negative sign indicates movement from high to low concentration.
Scaling for Total Rate
To find the total rate of diffusion, multiply the flux (J) by the total surface area (A) through which the substance is diffusing.
Note: A larger surface area provides more 'doors' for particles to pass through.
Approximating the Gradient
In biological systems, we approximate the steepness of the gradient as the difference in concentration between two sides (ΔC) divided by the thickness of the membrane (Δx or diffusion distance).
Note: A shorter diffusion distance results in a steeper gradient.
Combining Proportionalities
Substituting the flux and gradient approximation into the rate equation shows that the rate is directly proportional to surface area and concentration difference, and inversely proportional to the diffusion distance.
Note: In exams, ensure you mention that this only applies to passive transport.
Result
Source: AQA/OCR/Edexcel A-Level Biology Specification: Exchange and Transport
Why it behaves this way
Intuition
Think of the rate of diffusion like a busy train station platform. The 'Surface Area' is the number of open doors; more doors mean more people can exit at once. The 'Concentration Gradient' is the size of the crowd pushing from behind; the more people packed on one side compared to the other, the faster they spill out. The 'Diffusion Distance' is the thickness of the doorway itself; a thin door allows a quick dash, whereas a long, narrow tunnel slows everyone down significantly.
Signs and relationships
- ∝: Indicates direct proportionality to the numerator terms and inverse proportionality to the denominator, showing how changes in each variable scale the overall rate.
- Numerator: Factors on top increase the rate; as surface area or concentration gradient rise, the diffusion flux increases.
- Denominator: The diffusion distance acts as a 'bottleneck'; as it increases, the rate decreases, representing an inverse relationship.
One free problem
Practice Problem
Practice Problem 1
If the surface area of a membrane is 10 units, the concentration gradient is 2 units, and the diffusion distance is 4 units, calculate the relative rate of diffusion.
Solve for: rate
Hint: Multiply the area by the gradient and divide by the distance.
Practice Problem 2
A cell membrane has a diffusion rate of 12. If the surface area is 20 and the diffusion distance is 2, what is the concentration gradient?
Solve for: deltaC
Hint: Rearrange the formula to solve for C: C = (Rate * d) / A.
Practice Problem 3
To double the rate of diffusion while keeping the concentration gradient constant, and reducing the surface area by half, by what factor must the diffusion distance be changed?
Solve for:
Hint: Set up the ratio: 2 = (0.5 * 1) / d_new. Solve for d_new.
The full worked solution stays in the interactive walkthrough.
Where it shows up
Real-World Context
In human lungs, the millions of alveoli provide a massive surface area, while the thin squamous epithelium minimizes diffusion distance to facilitate rapid gas exchange.
Study smarter
Tips
- Remember that the rate is 'directly proportional' to the numerator terms and 'inversely proportional' to the denominator.
- Always convert units to be consistent before performing calculations.
- Think of it as 'maximizing the numerator' and 'minimizing the denominator' to optimize diffusion.
Avoid these traps
Common Mistakes
- Assuming diffusion stops when the concentration gradient reaches zero (it reaches dynamic equilibrium).
- Confusing 'diffusion distance' with 'total path length' instead of the membrane thickness specifically.
Common questions
Frequently Asked Questions
Fick's Law relates the rate of molecular diffusion to the physical properties of a membrane and the chemical gradient across it. It is derived from the observation of mass flux in a steady-state system.
Apply this when calculating factors affecting the efficiency of gas exchange surfaces or cellular diffusion rates.
It explains why respiratory surfaces (like gills or lungs) are highly branched or folded and why capillary walls are only one cell thick.
Assuming diffusion stops when the concentration gradient reaches zero (it reaches dynamic equilibrium). Confusing 'diffusion distance' with 'total path length' instead of the membrane thickness specifically.
In human lungs, the millions of alveoli provide a massive surface area, while the thin squamous epithelium minimizes diffusion distance to facilitate rapid gas exchange.
Remember that the rate is 'directly proportional' to the numerator terms and 'inversely proportional' to the denominator. Always convert units to be consistent before performing calculations. Think of it as 'maximizing the numerator' and 'minimizing the denominator' to optimize diffusion.
References
Sources
- Taylor, D. J., Green, N. P. O., & Stout, G. W. (2001). Biological Science 1 & 2. Cambridge University Press.
- Campbell, N. A., & Reece, J. B. (2005). Biology. Pearson Education.
- Toole, G., & Toole, S. (2015). A Level Biology for OCR A. Oxford University Press.
- Fick, A. (1855). Ueber Diffusion. Annalen der Physik.
- AQA/OCR/Edexcel A-Level Biology Specification: Exchange and Transport