Electric Field (Point Charge)
Field strength due to a point charge.
This public page keeps the free explanation visible and leaves premium worked solving, advanced walkthroughs, and saved study tools inside the app.
Core idea
Overview
This equation defines the magnitude of the electric field produced by a stationary point charge in a vacuum. It describes how the field strength is directly proportional to the quantity of charge and decreases according to the inverse square of the distance from that charge.
When to use: Apply this formula when calculating the field intensity at a specific point in space surrounding a single, isolated charged particle. It assumes the charge is concentrated at a single point and that the surrounding environment is a vacuum or air, where the permittivity of free space is applicable.
Why it matters: This principle is the cornerstone of electrostatics, explaining how particles exert forces on each other without direct contact. It is essential for engineering electronic sensors, managing high-voltage insulation, and understanding the behavior of subatomic particles in physics research.
Symbols
Variables
E = Field Strength, Q = Charge, \epsilon_0 = Permittivity, r = Distance
Walkthrough
Derivation
Derivation of Electric Field (Point Charge)
Calculates the electric field strength at a distance from a point charge, derived from Coulomb's Law.
- The source charge is a point charge or a uniform spherical charge.
- The test charge is small enough not to distort the field.
Start with Coulomb's Law:
This is the force between a source charge Q and a test charge q separated by distance r.
Apply the Definition of Electric Field:
Electric field strength is defined as the force per unit positive charge.
Substitute and Simplify:
The test charge q cancels out, leaving the field strength dependent only on the source charge Q and the distance squared.
Result
Source: OCR A-Level Physics A — Electric Fields
Free formulas
Rearrangements
Solve for
Make E the subject
E is already the subject of the formula.
Difficulty: 1/5
Solve for
Make Q the subject
To make the subject of the Electric Field (Point Charge) formula, multiply both sides by to isolate on one side of the equation.
Difficulty: 2/5
Solve for
Make epsilon0 the subject
Rearrange the Electric Field (Point Charge) formula to make (permittivity of free space) the subject. This involves multiplying by the denominator, grouping the remaining terms, and dividing to isolate .
Difficulty: 2/5
Solve for
Make r the subject
To make r the subject from the electric field strength equation, first clear the denominator, then isolate r², and finally take the square root.
Difficulty: 2/5
The static page shows the finished rearrangements. The app keeps the full worked algebra walkthrough.
Visual intuition
Graph
The graph displays an inverse-square relationship where field strength drops rapidly as distance increases, restricted to positive values with the axes acting as asymptotes. For a student, this means that very small distances result in an extremely intense field, while large distances cause the field strength to weaken significantly. The most important feature is that the curve never reaches zero, meaning the influence of a point charge theoretically extends across all space regardless of how far away you move.
Graph type: power_law
Why it behaves this way
Intuition
Imagine a point charge as a central source from which electric field lines emanate uniformly in all directions, spreading out over increasingly larger spherical surfaces, causing the field's intensity to diminish rapidly
Signs and relationships
- r^2 in the denominator: The inverse square dependence (1/) arises because electric field lines from a point charge spread out uniformly in three dimensions.
- The overall positive value of E: This formula calculates the magnitude of the electric field strength, which is always a positive scalar quantity. The direction of the electric field (radially outward or inward)
Free study cues
Insight
Canonical usage
This equation is almost universally applied using SI units for all quantities.
Common confusion
Forgetting to convert charge (Q) from non-SI units (e.g., microcoulombs) to Coulombs (C) or distance (r) from centimeters to meters (m) before calculation.
Unit systems
One free problem
Practice Problem
Calculate the magnitude of the electric field at a point 3.0 meters away from a point charge of 1.0 microCoulomb in a vacuum.
Solve for:
Hint: Convert 1.0 microCoulomb to 10⁻⁶ Coulombs and calculate r² as 9.0.
The full worked solution stays in the interactive walkthrough.
Where it shows up
Real-World Context
Estimating field strength near a charged sphere.
Study smarter
Tips
- Ensure the distance r is measured in meters and squared in the denominator.
- The constant 1/(4πε₀) is approximately 8.99 × 10⁹ N·m²/C², which can simplify mental checks.
- The electric field is a vector; this formula provides the magnitude, while the charge sign determines direction.
- Always convert micro-Coulombs (µC) or nano-Coulombs (nC) to standard Coulombs before calculation.
Avoid these traps
Common Mistakes
- Using r instead of r².
- Mixing microcoulombs and coulombs.
Common questions
Frequently Asked Questions
Calculates the electric field strength at a distance from a point charge, derived from Coulomb's Law.
Apply this formula when calculating the field intensity at a specific point in space surrounding a single, isolated charged particle. It assumes the charge is concentrated at a single point and that the surrounding environment is a vacuum or air, where the permittivity of free space is applicable.
This principle is the cornerstone of electrostatics, explaining how particles exert forces on each other without direct contact. It is essential for engineering electronic sensors, managing high-voltage insulation, and understanding the behavior of subatomic particles in physics research.
Using r instead of r². Mixing microcoulombs and coulombs.
Estimating field strength near a charged sphere.
Ensure the distance r is measured in meters and squared in the denominator. The constant 1/(4πε₀) is approximately 8.99 × 10⁹ N·m²/C², which can simplify mental checks. The electric field is a vector; this formula provides the magnitude, while the charge sign determines direction. Always convert micro-Coulombs (µC) or nano-Coulombs (nC) to standard Coulombs before calculation.
References
Sources
- Halliday, Resnick, and Walker, Fundamentals of Physics, 10th ed.
- Griffiths, David J. Introduction to Electrodynamics, 4th ed.
- Wikipedia: Electric field
- NIST CODATA: Permittivity of vacuum
- NIST CODATA
- Halliday, Resnick, and Walker, Fundamentals of Physics
- Halliday, Resnick, and Walker Fundamentals of Physics
- Wikipedia article Electric field