ChemistryQuantitative ChemistryA-Level

Moles from Concentration and Volume Calculator

Calculates the amount of substance in moles by multiplying the molar concentration of a solution by its volume.

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Moles

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Overview

This fundamental relationship defines molarity as the number of moles per unit volume. It is essential for stoichiometry calculations in liquid-phase reactions where precise control over reactant quantities is required. Ensuring volume units are consistent, usually in cubic decimeters (dm³), is critical for accurate results.

Symbols

Variables

n = Moles, c = Concentration (mol/dm³), V = Volume (dm³)

Moles
Variable
Concentration (mol/dm³)
Variable
Volume (dm³)
Variable

Apply it well

When To Use

When to use: Use this when you are given the concentration of a solution and the volume used in a reaction to determine the reacting moles.

Why it matters: It allows chemists to determine the exact amount of chemical species present in a known volume of liquid, which is the basis for volumetric analysis and titration.

Avoid these traps

Common Mistakes

  • Forgetting to convert cm³ to dm³ (dividing by 1000).
  • Confusing molarity (M) with mass concentration (g/dm³).

One free problem

Practice Problem

Calculate the number of moles in 2.0 of a 0.5 mol/ solution of sodium chloride.

Concentration (mol/dm³)0.5
Volume (dm³)2

Solve for:

Hint: Multiply the concentration by the volume directly.

The full worked solution stays in the interactive walkthrough.

References

Sources

  1. Atkins, P., & Jones, L. (2010). Chemical Principles: The Quest for Insight.
  2. OpenStax Chemistry 2e, Section 4.2
  3. A-Level Chemistry Specification (OCR/AQA/Edexcel)
  4. IUPAC Green Book: Quantities, Units and Symbols in Physical Chemistry
  5. AQA/OCR/Edexcel A-Level Chemistry Specification: Quantitative Chemistry